What is (\partial)/(\partial z)(-yz) ?

The answer to (\partial)/(\partial z)(-yz) is -y

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(\partial)/(\partial z)(-yz)

\frac{\partial}{\partial z} (- yz)

- y

Solution steps

\frac{\partial}{\partial z} (- yz)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - y \frac{\partial}{\partial z} (z)

Apply the common derivative:

\frac{\partial}{\partial z} (z) = 1

= - y \cdot 1

Simplify

= - y

x \to - 1 - lim (\frac{1}{x ^{2} - 1})

\int 8 x + 7 d x

x \to 0 lim (\frac{2 ^{x} - 1}{x})

y = 8 x, y = \frac{5}{2} x, y = 84 - x^{2}

\int (\frac{5}{x} - 3 e^{x}) d x

What is (\partial)/(\partial z)(-yz) ?
The answer to (\partial)/(\partial z)(-yz) is -y