What is the integral from 4 to 9 of sqrt(x) ?

The integral from 4 to 9 of sqrt(x) is 38/3

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integral from 4 to 9 of sqrt(x)

\int_{4}^{9} x d x

\frac{38}{3}

Decimal

12.66666 \dots

Solution steps

\int_{4}^{9} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{4}^{9}

= [\frac{2}{3} x^{\frac{3}{2}}]_{4}^{9}

Compute the boundaries:

\frac{38}{3}

= \frac{38}{3}

f (x) = sin (x) + x cos (x)

f (x) = x + 3

t y^{^{'}} + 4 y = t^{2} - t + 1

f (x) = \frac{1}{x ^{5}}

\int 3 x cos (x) d x

What is the integral from 4 to 9 of sqrt(x) ?
The integral from 4 to 9 of sqrt(x) is 38/3