What is the solution for (dy)/(dx)+20y=24 ?

The solution for (dy)/(dx)+20y=24 is y=-(e^{-20x-c_{1}})/5+6/5

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(dy)/(dx)+20y=24

\frac{d y}{d x} + 20 y = 24

y = - \frac{e ^{- 20 x - c_{1}}}{5} + \frac{6}{5}

Solution steps

\frac{d y}{d x} + 20 y = 24

Solve separable ODE:

y = - \frac{e ^{- 20 x - c_{1}}}{5} + \frac{6}{5}

y = - \frac{e ^{- 20 x - c_{1}}}{5} + \frac{6}{5}

∣ 4 x ∣, x^{2} - 5

x^{2}, 3 x

y^{^{''}} + 2 y^{^{'}} + y = sin (x) + 9 cos (2 x)

\int 1 + sin^{2} (x) d x

x \to - 2 lim (x)

What is the solution for (dy)/(dx)+20y=24 ?
The solution for (dy)/(dx)+20y=24 is y=-(e^{-20x-c_{1}})/5+6/5