en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+2y^'=1

Solution

y^{^{''}} + 2 y^{^{'}} = 1

Solution

y = c_{1} + c_{2} e^{- 2 t} + \frac{t}{2}

Solution steps

y^{''} (t) + 2 y^{'} (t) = 1

Solve linear ODE:

y = c_{1} + c_{2} e^{- 2 t} + \frac{t}{2}

y = c_{1} + c_{2} e^{- 2 t} + \frac{t}{2}

Graph

Popular Examples

y^{''}-10y^'+25y=((-3e^{5x}))/((x^2+1))

y^{^{''}} - 10 y^{^{'}} + 25 y = \frac{( - 3 e ^{5 x} )}{( x ^{2} + 1 )}

derivative of-2+7/(4x)

\frac{d}{d x} (- 2 + \frac{7}{4 x})

derivative of 12sqrt(x)derivative of

12 x

integral of (3x+2)^{1/2}

\int (3 x + 2)^{\frac{1}{2}} d x

integral of 7/(1+x^2)

\int \frac{7}{1 + x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+2y^'=1 ?
The solution for y^{''}+2y^'=1 is y=c_{1}+c_{2}e^{-2t}+t/2