What is the derivative of f(x)=-csc(x)-sin(x) ?

The derivative of f(x)=-csc(x)-sin(x) is cot^2(x)cos(x)

What is the first derivative of f(x)=-csc(x)-sin(x) ?

The first derivative of f(x)=-csc(x)-sin(x) is cot^2(x)cos(x)

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derivative of

f (x) = - csc (x) - sin (x)

cot^{2} (x) cos (x)

Solution steps

\frac{d}{d x} (- csc (x) - sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (csc (x)) - \frac{d}{d x} (sin (x))

\frac{d}{d x} (csc (x)) = - cot (x) csc (x)

\frac{d}{d x} (sin (x)) = cos (x)

= - (- cot (x) csc (x)) - cos (x)

Simplify

- (- cot (x) csc (x)) - cos (x) : cot^{2} (x) cos (x)

= cot^{2} (x) cos (x)

\frac{d}{d x} (3 x^{2} + x + 1)

\int_{1}^{e^{3}} \frac{ln ^{2} ( x ^{2} )}{x} d x

e^{t - 2}

f (t) = 3 e^{t}

\frac{d}{d x} (ln (1 - \frac{1}{x ^{2}}))

What is the derivative of f(x)=-csc(x)-sin(x) ?
The derivative of f(x)=-csc(x)-sin(x) is cot^2(x)cos(x)
What is the first derivative of f(x)=-csc(x)-sin(x) ?
The first derivative of f(x)=-csc(x)-sin(x) is cot^2(x)cos(x)