What is the derivative of f(x)=x^2+7 ?

The derivative of f(x)=x^2+7 is 2x

What is the first derivative of f(x)=x^2+7 ?

The first derivative of f(x)=x^2+7 is 2x

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derivative of

f (x) = x^{2} + 7

2 x

Solution steps

\frac{d}{d x} (x^{2} + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (7)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (7) = 0

= 2 x + 0

Simplify

= 2 x

\frac{d}{d x} (x^{0.1})

\frac{\partial}{\partial y} (arctan (y))

y = x^{2} + 3, (- 2, 4)

\frac{d}{d x} (4^{9 - x^{2}})

\int \frac{1}{1 + y ^{2}} d y

What is the derivative of f(x)=x^2+7 ?
The derivative of f(x)=x^2+7 is 2x
What is the first derivative of f(x)=x^2+7 ?
The first derivative of f(x)=x^2+7 is 2x