What is the solution for y^{''}-12y^'+36y=0,y(0)=1,y(1)=0 ?

The solution for y^{''}-12y^'+36y=0,y(0)=1,y(1)=0 is y=e^{6t}-e^{6t}t

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y^{''}-12y^'+36y=0,y(0)=1,y(1)=0

y^{^{''}} - 12 y^{^{'}} + 36 y = 0, y (0) = 1, y (1) = 0

y = e^{6 t} - e^{6 t} t

Solution steps

y^{''} (t) - 12 y^{'} (t) + 36 y = 0

Solve linear ODE:

y = e^{6 t} - e^{6 t} t

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What is the solution for y^{''}-12y^'+36y=0,y(0)=1,y(1)=0 ?
The solution for y^{''}-12y^'+36y=0,y(0)=1,y(1)=0 is y=e^{6t}-e^{6t}t