What is the derivative of-2sin(θ) ?

The derivative of-2sin(θ) is -2cos(θ)

What is the first derivative of-2sin(θ) ?

The first derivative of-2sin(θ) is -2cos(θ)

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derivative of

- 2 sin (θ)

- 2 cos (θ)

Solution steps

\frac{d}{d θ} (- 2 sin (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d θ} (sin (θ))

Apply the common derivative:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= - 2 cos (θ)

\frac{d}{d x} (x^{8 s i n (x)})

\frac{d y}{d x} = y^{4}

\frac{\partial}{\partial y} (sin (π (4 x - 6 y)))

x \to 0 lim (\frac{1}{x ^{4}})

\frac{d}{d y} (2 y^{2})

What is the derivative of-2sin(θ) ?
The derivative of-2sin(θ) is -2cos(θ)
What is the first derivative of-2sin(θ) ?
The first derivative of-2sin(θ) is -2cos(θ)