What is the derivative of f(x)=(x^4)/8-8x ?

The derivative of f(x)=(x^4)/8-8x is (x^3)/2-8

What is the first derivative of f(x)=(x^4)/8-8x ?

The first derivative of f(x)=(x^4)/8-8x is (x^3)/2-8

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derivative of

f (x) = \frac{x ^{4}}{8} - 8 x

\frac{x ^{3}}{2} - 8

Solution steps

\frac{d}{d x} (\frac{x ^{4}}{8} - 8 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{4}}{8}) - \frac{d}{d x} (8 x)

\frac{d}{d x} (\frac{x ^{4}}{8}) = \frac{x ^{3}}{2}

\frac{d}{d x} (8 x) = 8

= \frac{x ^{3}}{2} - 8

x \to \infty lim (5 + \frac{1}{x})

\frac{d}{d x} ((x^{2} + 1)^{x})

x \to 3 lim (4 + 4 (- 4))

\int 7 x e^{- 2 x} d x

\frac{d}{d x} (cos ((x^{2} + 6)^{5}))

What is the derivative of f(x)=(x^4)/8-8x ?
The derivative of f(x)=(x^4)/8-8x is (x^3)/2-8
What is the first derivative of f(x)=(x^4)/8-8x ?
The first derivative of f(x)=(x^4)/8-8x is (x^3)/2-8