What is the tangent of f(x)=(4x)/(x+2),\at x=6 ?

The tangent of f(x)=(4x)/(x+2),\at x=6 is y= 1/8 x+9/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=(4x)/(x+2),\at x=6

tangent of

f (x) = \frac{4 x}{x + 2}, at x = 6

y = \frac{1}{8} x + \frac{9}{4}

Solution steps

Find the tangent point:

(6, 3)

Find the slope of

f (x) = \frac{4 x}{x + 2} : \frac{df ( x )}{d x} = \frac{8}{( x + 2 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{8}

Find the line with slope m=

\frac{1}{8}

and passing through

(6, 3) : y = \frac{1}{8} x + \frac{9}{4}

y = \frac{1}{8} x + \frac{9}{4}

\frac{d}{d x} (3 x + 8)

\int cos^{2} (x t a) n^{3} x d x

3 u + 5 u

y^{^{'}} = 4 - 9^{2} - 6 x^{5}

\frac{d}{d x} (\frac{1}{4 x ^{5}})

What is the tangent of f(x)=(4x)/(x+2),\at x=6 ?
The tangent of f(x)=(4x)/(x+2),\at x=6 is y= 1/8 x+9/4