What is (\partial)/(\partial x)(y^2-cos(x)y) ?

The answer to (\partial)/(\partial x)(y^2-cos(x)y) is ysin(x)

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(\partial)/(\partial x)(y^2-cos(x)y)

\frac{\partial}{\partial x} (y^{2} - cos (x) y)

y sin (x)

Solution steps

\frac{\partial}{\partial x} (y^{2} - cos (x) y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (cos (x) y)

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (cos (x) y) = - y sin (x)

= 0 - (- y sin (x))

Simplify

= y sin (x)

\frac{d}{d x} (540 (1 - e^{- 0.1 x}))

n = 3 \sum \infty \frac{2}{n ^{2} + 1}

\int \frac{( ln ^{3} ( x ) )}{x} d x

2 y^{^{'}} - y = e^{\frac{t}{3}}

f (x) = 5 ln (x)

What is (\partial)/(\partial x)(y^2-cos(x)y) ?
The answer to (\partial)/(\partial x)(y^2-cos(x)y) is ysin(x)