What is the derivative of (2x/((x^2+1))) ?

The derivative of (2x/((x^2+1))) is (2(-x^2+1))/((x^2+1)^2)

What is the first derivative of (2x/((x^2+1))) ?

The first derivative of (2x/((x^2+1))) is (2(-x^2+1))/((x^2+1)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{2 x}{( x ^{2} + 1 )})

\frac{2 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x}{( x ^{2} + 1 )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{x}{x ^{2} + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d x}{d x} ( x ^{2} + 1 ) - \frac{d}{d x} ( x ^{2} + 1 ) x}{( x ^{2} + 1 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 1) = 2 x

= 2 \cdot \frac{1 \cdot ( x ^{2} + 1 ) - 2 xx}{( x ^{2} + 1 ) ^{2}}

Simplify

2 \cdot \frac{1 \cdot ( x ^{2} + 1 ) - 2 xx}{( x ^{2} + 1 ) ^{2}} : \frac{2 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

= \frac{2 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

x \to 5 lim ((6 + \frac{1}{x})^{2})

\int \frac{21}{x ln ( 8 x )} d x

y^{2} - 5 x = 1, x - y = 1

9 x^{2} + y^{2} = 9

\int \frac{2 ^{x} 3 ^{x} 5 ^{x}}{2} d x

What is the derivative of (2x/((x^2+1))) ?
The derivative of (2x/((x^2+1))) is (2(-x^2+1))/((x^2+1)^2)
What is the first derivative of (2x/((x^2+1))) ?
The first derivative of (2x/((x^2+1))) is (2(-x^2+1))/((x^2+1)^2)