What is the limit as x approaches 4 of [4f(8)g(-1)] ?

The limit as x approaches 4 of [4f(8)g(-1)] is 4f(8)g(-1)

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limit as x approaches 4 of [4f(8)g(-1)]

x \to 4 lim ([4 f (8) g (- 1)])

4 f (8) g (- 1)

Solution steps

x \to 4 lim (4 f (8) g (- 1))

x \to a lim c = c

= 4 f (8) g (- 1)

\int \frac{1}{y ^{2} - 2} d y

2 (t - 2)^{2} + 6 (t - 2) + 6

\int \frac{1}{4 x ^{2} - 16} d x

\int \frac{2}{x ^{2} - 4 x + 13} d x

n = 0 \sum \infty \frac{1}{n ^{4}}

What is the limit as x approaches 4 of [4f(8)g(-1)] ?
The limit as x approaches 4 of [4f(8)g(-1)] is 4f(8)g(-1)