What is the derivative of f(x)=x^4-2x^3+x-1 ?

The derivative of f(x)=x^4-2x^3+x-1 is 4x^3-6x^2+1

What is the first derivative of f(x)=x^4-2x^3+x-1 ?

The first derivative of f(x)=x^4-2x^3+x-1 is 4x^3-6x^2+1

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derivative of

f (x) = x^{4} - 2 x^{3} + x - 1

4 x^{3} - 6 x^{2} + 1

Solution steps

\frac{d}{d x} (x^{4} - 2 x^{3} + x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (2 x^{3}) + \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 4 x^{3} - 6 x^{2} + 1 - 0

Simplify

= 4 x^{3} - 6 x^{2} + 1

\frac{d}{d t} (e^{r (t) t})

- x^{2} + 9 x, x^{2} - 5 x

y = 3 - 5 x

\int_{4}^{9} \frac{1}{8 - x} d x

\int e^{- x t} d x

What is the derivative of f(x)=x^4-2x^3+x-1 ?
The derivative of f(x)=x^4-2x^3+x-1 is 4x^3-6x^2+1
What is the first derivative of f(x)=x^4-2x^3+x-1 ?
The first derivative of f(x)=x^4-2x^3+x-1 is 4x^3-6x^2+1