What is the derivative of f(x)=25^x ?

The derivative of f(x)=25^x is 2ln(5)*25^x

What is the first derivative of f(x)=25^x ?

The first derivative of f(x)=25^x is 2ln(5)*25^x

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derivative of

f (x) = 2 5^{x}

2 ln (5) \cdot 2 5^{x}

Solution steps

\frac{d}{d x} (2 5^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 2 5^{x} ln (25)

Simplify

ln (25) : 2 ln (5)

= 2 ln (5) \cdot 2 5^{x}

\int - 6 x (- 4 x^{2} + 6)^{5} d x

\int \frac{9}{15 sin ( x ) - 8 cos ( x )} d x

\frac{d}{d x} (\frac{2 x}{a ^{2} - x ^{2}})

n = 1 \sum \infty \frac{1}{4 n ^{2} + 7}

y^{^{''}} + a y = 0, y (0) = 1, y (1) = 0

What is the derivative of f(x)=25^x ?
The derivative of f(x)=25^x is 2ln(5)*25^x
What is the first derivative of f(x)=25^x ?
The first derivative of f(x)=25^x is 2ln(5)*25^x