What is the integral of (tan^2(y)+1) ?

The integral of (tan^2(y)+1) is tan(y)+C

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integral of (tan^2(y)+1)

\int (tan^{2} (y) + 1) d y

tan (y) + C

Solution steps

\int tan^{2} (y) + 1 d y

Rewrite using trig identities

= \int sec^{2} (y) d y

Use the common integral:

\int sec^{2} (y) d y = tan (y)

= tan (y)

Add a constant to the solution

= tan (y) + C

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