What is the limit as t approaches 2 of ln(t^3) ?

The limit as t approaches 2 of ln(t^3) is 3ln(2)

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limit as t approaches 2 of ln(t^3)

t \to 2 lim (ln (t^{3}))

3 ln (2)

Decimal

2.07944 \dots

Solution steps

t \to 2 lim (ln (t^{3}))

Plug in the value

t = 2

= ln (2^{3})

Apply log rule

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x),

assuming

x \geq 0

= 3 ln (2)

(\frac{1}{x}) d y = sin (x) (y^{3} + y) d x

x \to 0 - lim (e^{- x})

f (x) = \frac{7}{x}, at x = 2, x = 7

\frac{\partial}{\partial y} (3 x^{2} + 3 y^{2} - 15)

y = 1 - x

What is the limit as t approaches 2 of ln(t^3) ?
The limit as t approaches 2 of ln(t^3) is 3ln(2)