What is the solution for e^xydy-(e^{-y}+e^{-2x-y})dx=0 ?

The solution for e^xydy-(e^{-y}+e^{-2x-y})dx=0 is y=\W((-1/(e^{3x)}-3/(e^x)+c_{1})/(3e))+1

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e^xydy-(e^{-y}+e^{-2x-y})dx=0

e^{x} y d y - (e^{- y} + e^{- 2 x - y}) d x = 0

y = W (\frac{- \frac{1}{e ^{3 x}} - \frac{3}{e ^{x}} + c _{1}}{3 e}) + 1

Solution steps

e^{x} y d y - (e^{- y} + e^{- 2 x - y}) d x = 0

Solve separable ODE:

y = W (\frac{- \frac{1}{e ^{3 x}} - \frac{3}{e ^{x}} + c _{1}}{3 e}) + 1

y = W (\frac{- \frac{1}{e ^{3 x}} - \frac{3}{e ^{x}} + c _{1}}{3 e}) + 1

\int - 2 e^{4 x} d x

\frac{\partial}{\partial x} (x^{- 1})

\frac{s + 2}{s ( s + 1 ) ( s + 3 )}

\frac{\partial}{\partial x} (sin (2 x) + cos (3 y))

e^{x} (1)

What is the solution for e^xydy-(e^{-y}+e^{-2x-y})dx=0 ?
The solution for e^xydy-(e^{-y}+e^{-2x-y})dx=0 is y=\W((-1/(e^{3x)}-3/(e^x)+c_{1})/(3e))+1