What is the derivative of 8+sqrt(x-7) ?

The derivative of 8+sqrt(x-7) is 1/(2sqrt(x-7))

What is the first derivative of 8+sqrt(x-7) ?

The first derivative of 8+sqrt(x-7) is 1/(2sqrt(x-7))

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derivative of

8 + x - 7

\frac{1}{2 x - 7}

Solution steps

\frac{d}{d x} (8 + x - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8) + \frac{d}{d x} (x - 7)

\frac{d}{d x} (8) = 0

\frac{d}{d x} (x - 7) = \frac{1}{2 x - 7}

= 0 + \frac{1}{2 x - 7}

Simplify

= \frac{1}{2 x - 7}

y^{^{''}} - x = 0

x \to 1 lim (ln (x^{4} - 3 x + 10))

x \to - 3 + lim (\frac{x ^{2}}{x + 3})

\int arctan (3 x) d x

f (x) = 24 e^{x}, at x = 2

What is the derivative of 8+sqrt(x-7) ?
The derivative of 8+sqrt(x-7) is 1/(2sqrt(x-7))
What is the first derivative of 8+sqrt(x-7) ?
The first derivative of 8+sqrt(x-7) is 1/(2sqrt(x-7))