What is the derivative of 9(x-4)^{2/3} ?

The derivative of 9(x-4)^{2/3} is 6/((x-4)^{1/3)}

What is the first derivative of 9(x-4)^{2/3} ?

The first derivative of 9(x-4)^{2/3} is 6/((x-4)^{1/3)}

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derivative of

9 (x - 4)^{\frac{2}{3}}

\frac{6}{( x - 4 ) ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} (9 (x - 4)^{\frac{2}{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} ((x - 4)^{\frac{2}{3}})

Apply the chain rule:

\frac{2}{3 ( x - 4 ) ^{\frac{1}{3}}} \frac{d}{d x} (x - 4)

= \frac{2}{3 ( x - 4 ) ^{\frac{1}{3}}} \frac{d}{d x} (x - 4)

\frac{d}{d x} (x - 4) = 1

= 9 \cdot \frac{2}{3 ( x - 4 ) ^{\frac{1}{3}}} \cdot 1

Simplify

9 \cdot \frac{2}{3 ( x - 4 ) ^{\frac{1}{3}}} \cdot 1 : \frac{6}{( x - 4 ) ^{\frac{1}{3}}}

= \frac{6}{( x - 4 ) ^{\frac{1}{3}}}

\frac{d}{d x} (210)

\frac{d}{d x} (\frac{e ^{- x^{2}}}{x ^{3}})

ln (6 - x^{2} + 2 x^{4})

\int_{1}^{\infty} \frac{7}{x ^{2} + 1} d x

y = ((\frac{x ^{2} - 2}{2 x ^{2} + 1})^{2})

What is the derivative of 9(x-4)^{2/3} ?
The derivative of 9(x-4)^{2/3} is 6/((x-4)^{1/3)}
What is the first derivative of 9(x-4)^{2/3} ?
The first derivative of 9(x-4)^{2/3} is 6/((x-4)^{1/3)}