What is the tangent of-3x^3-2x^2-1,\at x=-1 ?

The tangent of-3x^3-2x^2-1,\at x=-1 is y=-5x-5

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tangent of-3x^3-2x^2-1,\at x=-1

tangent of

- 3 x^{3} - 2 x^{2} - 1, at x = - 1

y = - 5 x - 5

Solution steps

Find the tangent point:

(- 1, 0)

Find the slope of

y = - 3 x^{3} - 2 x^{2} - 1 : \frac{d y}{d x} = - 9 x^{2} - 4 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 5

Find the line with slope m=

- 5

and passing through

(- 1, 0) : y = - 5 x - 5

y = - 5 x - 5

\frac{d}{d x} (y sin (z (x)))

(3 x)^{2 x}

\int x^{3} x^{2} - 36 d x

y = \frac{6 x}{9 - tan ( x )}

\int - x^{4} e^{x} d x

What is the tangent of-3x^3-2x^2-1,\at x=-1 ?
The tangent of-3x^3-2x^2-1,\at x=-1 is y=-5x-5