What is the tangent of x^2+xy-y^2=-4,(2,4) ?

The tangent of x^2+xy-y^2=-4,(2,4) is y= 4/3 x+4/3

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tangent of x^2+xy-y^2=-4,(2,4)

tangent of

x^{2} + x y - y^{2} = - 4, (2, 4)

y = \frac{4}{3} x + \frac{4}{3}

Solution steps

Find the slope of

x^{2} + x y - y^{2} = - 4 : \frac{d y}{d x} = \frac{- 2 x - y}{x - 2 y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{4}{3}

Find the line with slope m=

\frac{4}{3}

and passing through

(2, 4) : y = \frac{4}{3} x + \frac{4}{3}

y = \frac{4}{3} x + \frac{4}{3}

(2 x - 1)^{3}

\int 3 + x d x

\int \frac{1}{x ^{2}} 1 + \frac{1}{x} d x

\int \frac{4 x ^{2}}{1 + x ^{3}} d x

\int 3 y 3 2 y^{2} - 8 d y

What is the tangent of x^2+xy-y^2=-4,(2,4) ?
The tangent of x^2+xy-y^2=-4,(2,4) is y= 4/3 x+4/3