What is the limit as x approaches 0 of 2f(x)-1 ?

The limit as x approaches 0 of 2f(x)-1 is 2f(0)-1

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limit as x approaches 0 of 2f(x)-1

x \to 0 lim (2 f (x) - 1)

2 f (0) - 1

Solution steps

x \to 0 lim (2 f (x) - 1)

Plug in the value

x = 0

, assuming the function is continuous at this point

= 2 f (0) - 1

y^{^{''}} + 16 y = 4 t^{2}

\int \frac{x ^{4} + 9}{x ^{2} + 9 x ^{2}} d x

x \to 0 lim ((1 + 2 x)^{- \frac{3}{x}})

\frac{\partial}{\partial x} (sin (π (5 x - 5 y)))

f (x) = \frac{x ^{3} - 8 x ^{2} + 5}{x ^{2}}

What is the limit as x approaches 0 of 2f(x)-1 ?
The limit as x approaches 0 of 2f(x)-1 is 2f(0)-1