What is the solution for x(dy)/(dx)=2xe^{x^2}-y+6x^2 ?

The solution for x(dy)/(dx)=2xe^{x^2}-y+6x^2 is y=(e^{x^2})/x+2x^2+(c_{1})/x

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x(dy)/(dx)=2xe^{x^2}-y+6x^2

x \frac{d y}{d x} = 2 x e^{x^{2}} - y + 6 x^{2}

y = \frac{e ^{x^{2}}}{x} + 2 x^{2} + \frac{c _{1}}{x}

Solution steps

x \frac{d y}{d x} = 2 x e^{x^{2}} - y + 6 x^{2}

Solve linear ODE:

y = \frac{e ^{x^{2}}}{x} + 2 x^{2} + \frac{c _{1}}{x}

y = \frac{e ^{x^{2}}}{x} + 2 x^{2} + \frac{c _{1}}{x}

y^{^{'}} + y - 3 cos (x) = 0

\frac{d y}{d x}, x^{5} + y^{5} = 35 x y

\frac{\partial}{\partial y} (e^{- 1 x} cos (6 y))

\frac{e ^{x}}{- 8 x ^{7}}

\frac{d}{d x} (\frac{x ^{5}}{e ^{x}})

What is the solution for x(dy)/(dx)=2xe^{x^2}-y+6x^2 ?
The solution for x(dy)/(dx)=2xe^{x^2}-y+6x^2 is y=(e^{x^2})/x+2x^2+(c_{1})/x