What is the derivative of (x^2+1)^3 ?

The derivative of (x^2+1)^3 is 6x(x^2+1)^2

What is the first derivative of (x^2+1)^3 ?

The first derivative of (x^2+1)^3 is 6x(x^2+1)^2

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derivative of

(x^{2} + 1)^{3}

6 x (x^{2} + 1)^{2}

Solution steps

\frac{d}{d x} ((x^{2} + 1)^{3})

Apply the chain rule:

3 (x^{2} + 1)^{2} \frac{d}{d x} (x^{2} + 1)

= 3 (x^{2} + 1)^{2} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= 3 (x^{2} + 1)^{2} \cdot 2 x

Simplify

= 6 x (x^{2} + 1)^{2}

y = \frac{2}{x - 8}

x \to 1 lim (\frac{1}{1 - x ^{2}})

\int 4 x^{2} + 4 x + 1 d x

\int \frac{1}{( y - 3 ) ^{2}} d y

\frac{\partial}{\partial z} (4 e^{x} cos (yz))

What is the derivative of (x^2+1)^3 ?
The derivative of (x^2+1)^3 is 6x(x^2+1)^2
What is the first derivative of (x^2+1)^3 ?
The first derivative of (x^2+1)^3 is 6x(x^2+1)^2