What is (\partial)/(\partial y)(e^x+yz) ?

The answer to (\partial)/(\partial y)(e^x+yz) is z

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(e^x+yz)

\frac{\partial}{\partial y} (e^{x} + yz)

z

Solution steps

\frac{\partial}{\partial y} (e^{x} + yz)

Treat

x, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (e^{x}) + \frac{\partial}{\partial y} (yz)

\frac{\partial}{\partial y} (e^{x}) = 0

\frac{\partial}{\partial y} (yz) = z

= 0 + z

Simplify

= z

\int \frac{1}{e ^{z} + e ^{- z}} d z

\frac{d}{d x} ((3 + x - 2 x^{2})^{\frac{1}{4}})

\frac{d y}{d x}, 4 x^{2} + 9 y^{2} = 36

y^{^{'}} + 2 x y = x e^{- x^{2}}

3 2690 - 10 x^{2}

What is (\partial)/(\partial y)(e^x+yz) ?
The answer to (\partial)/(\partial y)(e^x+yz) is z