What is the derivative of-(x^2)/(y^2) ?

The derivative of-(x^2)/(y^2) is -(2x)/(y^2)

What is the first derivative of-(x^2)/(y^2) ?

The first derivative of-(x^2)/(y^2) is -(2x)/(y^2)

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derivative of

- \frac{x ^{2}}{y ^{2}}

- \frac{2 x}{y ^{2}}

Solution steps

\frac{d}{d x} (- \frac{x ^{2}}{y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{y ^{2}} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{y ^{2}} \cdot 2 x^{2 - 1}

Simplify

- \frac{1}{y ^{2}} \cdot 2 x^{2 - 1} : - \frac{2 x}{y ^{2}}

= - \frac{2 x}{y ^{2}}

\int \frac{( 2 x ^{2} + 4 x - 5 )}{x ^{2} ( x + 3 )} d x

\int_{1}^{3} x^{2} + 2 x - 2 d x

\int_{1}^{4} x^{\frac{3}{2}} ln (x) d x

\int_{0}^{1} \frac{1}{( x + 1 ) ^{2}} d x

f (t) = 3 t

What is the derivative of-(x^2)/(y^2) ?
The derivative of-(x^2)/(y^2) is -(2x)/(y^2)
What is the first derivative of-(x^2)/(y^2) ?
The first derivative of-(x^2)/(y^2) is -(2x)/(y^2)