What is the derivative of 1/(2x-1) ?

The derivative of 1/(2x-1) is -2/((2x-1)^2)

What is the first derivative of 1/(2x-1) ?

The first derivative of 1/(2x-1) is -2/((2x-1)^2)

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derivative of

\frac{1}{2 x - 1}

- \frac{2}{( 2 x - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x - 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((2 x - 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x - 1 ) ^{2}} \frac{d}{d x} (2 x - 1)

= - \frac{1}{( 2 x - 1 ) ^{2}} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= - \frac{1}{( 2 x - 1 ) ^{2}} \cdot 2

Simplify

- \frac{1}{( 2 x - 1 ) ^{2}} \cdot 2 : - \frac{2}{( 2 x - 1 ) ^{2}}

= - \frac{2}{( 2 x - 1 ) ^{2}}

x \to \infty + lim (e^{x} + 3)

f (x) = (2 x + 3)^{6} \cdot (x - 2)^{4}

f (x) = \frac{x}{x - 2}, (3, 3)

y^{^{''}} = y^{^{'}}

\int \frac{8}{z z ^{2} + 2} d z

What is the derivative of 1/(2x-1) ?
The derivative of 1/(2x-1) is -2/((2x-1)^2)
What is the first derivative of 1/(2x-1) ?
The first derivative of 1/(2x-1) is -2/((2x-1)^2)