What is the tangent of f(x)=x^2+7,(4,23) ?

The tangent of f(x)=x^2+7,(4,23) is y=8x-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2+7,(4,23)

tangent of

f (x) = x^{2} + 7, (4, 23)

y = 8 x - 9

Solution steps

Find the slope of

f (x) = x^{2} + 7 : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 8

Find the line with slope m=

8

and passing through

(4, 23) : y = 8 x - 9

y = 8 x - 9

\int 2 y + 4 e^{y} d y

z \to 3 lim (2 z^{3})

f (x) = x (x - 2)

\frac{1}{3} 3 x

\int_{4}^{10} \frac{( x - 4 ) ^{2}}{72} d x

What is the tangent of f(x)=x^2+7,(4,23) ?
The tangent of f(x)=x^2+7,(4,23) is y=8x-9