What is the integral from 1 to 3 of 3x^2 ?

The integral from 1 to 3 of 3x^2 is 26

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 3 of 3x^2

\int_{1}^{3} 3 x^{2} d x

26

Solution steps

\int_{1}^{3} 3 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{3} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{3}

= 3 [\frac{x ^{3}}{3}]_{1}^{3}

Compute the boundaries:

\frac{26}{3}

= 3 \cdot \frac{26}{3}

Simplify

= 26

x y^{^{'}} + 3 y = \frac{( 2 e ^{- 4 x} )}{x ^{2}}

\frac{d}{d x} (y (1 + e^{x}))

x \to 1 lim (0.9 9^{2 - 1})

\frac{d}{d x} (- \frac{13}{x ^{5}})

\frac{\partial}{\partial y} (- sin (x))

What is the integral from 1 to 3 of 3x^2 ?
The integral from 1 to 3 of 3x^2 is 26