What is the limit as x approaches 2 of (7x+4)/(3x+9) ?

The limit as x approaches 2 of (7x+4)/(3x+9) is 6/5

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limit as x approaches 2 of (7x+4)/(3x+9)

x \to 2 lim (\frac{7 x + 4}{3 x + 9})

\frac{6}{5}

Solution steps

x \to 2 lim (\frac{7 x + 4}{3 x + 9})

Plug in the value

x = 2

= \frac{7 \cdot 2 + 4}{3 \cdot 2 + 9}

Simplify

\frac{7 \cdot 2 + 4}{3 \cdot 2 + 9} : \frac{6}{5}

= \frac{6}{5}

\int \frac{( 3 ln ( x ) - 5 ) ^{4}}{x} d x

\int - tan (x) d x

\frac{d y}{d x} = x^{2} y

x y + (x^{2} + y^{2}) (\frac{d y}{d x}) = 0

What is the limit as x approaches 2 of (7x+4)/(3x+9) ?
The limit as x approaches 2 of (7x+4)/(3x+9) is 6/5