What is the limit as x approaches 0 of ((1+x)^2+1)/x ?

The limit as x approaches 0 of ((1+x)^2+1)/x is diverges

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limit as x approaches 0 of ((1+x)^2+1)/x

x \to 0 lim (\frac{( 1 + x ) ^{2} + 1}{x})

diverges

Solution steps

x \to 0 lim (\frac{( 1 + x ) ^{2} + 1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{( 1 + x ) ^{2} + 1}{x}) = \infty

x \to 0 - lim (\frac{( 1 + x ) ^{2} + 1}{x}) = - \infty

= diverges

y = 12 x, y = 4 x^{2}

\int \frac{cos ( x )}{sin ( x ) ( sin ( x ) - 1 )} d x

\int 8 x^{2} + 2 + \frac{5}{x ^{2} + 1} d x

f (x) = 3 x^{2} - 2

\frac{1}{5 x ^{2}}

What is the limit as x approaches 0 of ((1+x)^2+1)/x ?
The limit as x approaches 0 of ((1+x)^2+1)/x is diverges