What is the limit as x approaches 0 of 2/(sin(7x)) ?

The limit as x approaches 0 of 2/(sin(7x)) is diverges

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limit as x approaches 0 of 2/(sin(7x))

x \to 0 lim (\frac{2}{sin ( 7 x )})

diverges

Solution steps

x \to 0 lim (\frac{2}{sin ( 7 x )})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{2}{sin ( 7 x )}) = \infty

x \to 0 - lim (\frac{2}{sin ( 7 x )}) = - \infty

= diverges

n = 1 \sum \infty n^{\frac{1}{n}}

\int 7 x e^{5 x^{2}} d x

x \to 5 lim (5 x + 2)

y = x^{2} - 12 x + 4

x \to - 96 lim (97)

What is the limit as x approaches 0 of 2/(sin(7x)) ?
The limit as x approaches 0 of 2/(sin(7x)) is diverges