What is the limit as x approaches 5/7 of 1/(7x-5) ?

The limit as x approaches 5/7 of 1/(7x-5) is diverges

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limit as x approaches 5/7 of 1/(7x-5)

x \to \frac{5}{7} lim (\frac{1}{7 x - 5})

diverges

Solution steps

x \to \frac{5}{7} lim (\frac{1}{7 x - 5})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to \frac{5}{7} + lim (\frac{1}{7 x - 5}) = \infty

x \to \frac{5}{7} - lim (\frac{1}{7 x - 5}) = - \infty

= diverges

x \to 0 lim (\frac{8}{( 0.01 ) ^{3}})

t - t

f (x) = 4 - x, x = - 2, x = 6

\frac{\partial}{\partial x} (2 x + 2 y)

\int_{1}^{2} 9 - x^{2} d x

What is the limit as x approaches 5/7 of 1/(7x-5) ?
The limit as x approaches 5/7 of 1/(7x-5) is diverges