What is the integral of 5θcos(θ) ?

The integral of 5θcos(θ) is 5(θsin(θ)+cos(θ))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 5θcos(θ)

\int 5 θ cos (θ) d θ

5 (θ sin (θ) + cos (θ)) + C

Solution steps

\int 5 θ cos (θ) d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int θ cos (θ) d θ

Apply Integration By Parts

: θ sin (θ) - \int sin (θ) d θ

= 5 (θ sin (θ) - \int sin (θ) d θ)

\int sin (θ) d θ = - cos (θ)

= 5 (θ sin (θ) - (- cos (θ)))

Simplify

= 5 (θ sin (θ) + cos (θ))

Add a constant to the solution

= 5 (θ sin (θ) + cos (θ)) + C

a x + 1

\int (6 x^{3} + 7 3 x^{2}) d x

y = sec^{2} (x), y = sin (x), [0, \frac{π}{4}]

\int \frac{10 sin ( t )}{- 3 + 6 cos ( t )} d t

x \to 0 lim (e^{\frac{x}{x ^{2} - 4}})

What is the integral of 5θcos(θ) ?
The integral of 5θcos(θ) is 5(θsin(θ)+cos(θ))+C