What is the limit as x approaches 7-of ((2x+1))/(x-7) ?

The limit as x approaches 7-of ((2x+1))/(x-7) is -infinity

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limit as x approaches 7-of ((2x+1))/(x-7)

x \to 7 - lim (\frac{( 2 x + 1 )}{x - 7})

- \infty

Solution steps

x \to 7 - lim (\frac{2 x + 1}{x - 7})

\frac{2 x + 1}{x - 7} = (2 x + 1) \frac{1}{x - 7}

= x \to 7 - lim ((2 x + 1) \frac{1}{x - 7})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 7 - lim (2 x + 1) \cdot x \to 7 - lim (\frac{1}{x - 7})

x \to 7 - lim (2 x + 1) = 15

x \to 7 - lim (\frac{1}{x - 7}) = - \infty

= 15 (- \infty)

Apply Infinity Property:

c \cdot (- \infty) = - \infty

= - \infty

\frac{\partial}{\partial x} (\frac{7 y - 4 x}{y ^{2} + 2 x ^{2}})

\frac{d}{d x} (30 x)

\int (x^{8} - 4 x^{2})^{3} (x^{7} - x) d x

\frac{\partial}{\partial z} (x e^{y})

y = \frac{1}{2 x + 7}

What is the limit as x approaches 7-of ((2x+1))/(x-7) ?
The limit as x approaches 7-of ((2x+1))/(x-7) is -infinity