What is the derivative of ((x+1)/(x-1))^2 ?

The derivative of ((x+1)/(x-1))^2 is -(4(x+1))/((x-1)^3)

What is the first derivative of ((x+1)/(x-1))^2 ?

The first derivative of ((x+1)/(x-1))^2 is -(4(x+1))/((x-1)^3)

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derivative of

(\frac{x + 1}{x - 1})^{2}

- \frac{4 ( x + 1 )}{( x - 1 ) ^{3}}

Solution steps

\frac{d}{d x} ((\frac{x + 1}{x - 1})^{2})

Apply the chain rule:

2 \cdot \frac{x + 1}{x - 1} \frac{d}{d x} (\frac{x + 1}{x - 1})

= 2 \cdot \frac{x + 1}{x - 1} \frac{d}{d x} (\frac{x + 1}{x - 1})

\frac{d}{d x} (\frac{x + 1}{x - 1}) = - \frac{2}{( x - 1 ) ^{2}}

= 2 \cdot \frac{x + 1}{x - 1} (- \frac{2}{( x - 1 ) ^{2}})

Simplify

2 \cdot \frac{x + 1}{x - 1} (- \frac{2}{( x - 1 ) ^{2}}) : - \frac{4 ( x + 1 )}{( x - 1 ) ^{3}}

= - \frac{4 ( x + 1 )}{( x - 1 ) ^{3}}

\int \frac{y}{x ^{2}} d x

x \to 9 lim (x - 3)

\frac{d}{d x} (3^{\frac{1}{x}})

\frac{d}{d x} (lo g_{4} (5 x^{2} + 1))

\frac{d}{d x} (\frac{2 x}{4 + x ^{2}})

What is the derivative of ((x+1)/(x-1))^2 ?
The derivative of ((x+1)/(x-1))^2 is -(4(x+1))/((x-1)^3)
What is the first derivative of ((x+1)/(x-1))^2 ?
The first derivative of ((x+1)/(x-1))^2 is -(4(x+1))/((x-1)^3)