What is the derivative of sin(9x^2) ?

The derivative of sin(9x^2) is cos(9x^2)*18x

What is the first derivative of sin(9x^2) ?

The first derivative of sin(9x^2) is cos(9x^2)*18x

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\frac{d}{d x} (sin (9 x^{2}))

cos (9 x^{2}) \cdot 18 x

Solution steps

\frac{d}{d x} (sin (9 x^{2}))

Apply the chain rule:

cos (9 x^{2}) \frac{d}{d x} (9 x^{2})

= cos (9 x^{2}) \frac{d}{d x} (9 x^{2})

\frac{d}{d x} (9 x^{2}) = 18 x

= cos (9 x^{2}) \cdot 18 x

n = 1 \sum \infty \frac{1}{n} cos (nπ)

f (x) = x^{2} + 2 x, x = 3, x = 5

f (x) = ln (x^{2} + 3)

\frac{d}{d s} (\frac{e ^{- 2 s}}{s})

\frac{\partial}{\partial x} (\frac{x + 3}{x ^{2} - x - 2})

What is the derivative of sin(9x^2) ?
The derivative of sin(9x^2) is cos(9x^2)*18x
What is the first derivative of sin(9x^2) ?
The first derivative of sin(9x^2) is cos(9x^2)*18x