What is the solution for y^{''}+16y=0,y(0)=2,y^'(0)=0 ?

The solution for y^{''}+16y=0,y(0)=2,y^'(0)=0 is y=2cos(4t)

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y^{''}+16y=0,y(0)=2,y^'(0)=0

y^{^{''}} + 16 y = 0, y (0) = 2, y^{^{'}} (0) = 0

y = 2 cos (4 t)

Solution steps

y^{''} (t) + 16 y = 0

Solve linear ODE:

y = 2 cos (4 t)

y = 2 cos (4 t)

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What is the solution for y^{''}+16y=0,y(0)=2,y^'(0)=0 ?
The solution for y^{''}+16y=0,y(0)=2,y^'(0)=0 is y=2cos(4t)