What is the derivative of 2cos(2x) ?

The derivative of 2cos(2x) is -4sin(2x)

What is the first derivative of 2cos(2x) ?

The first derivative of 2cos(2x) is -4sin(2x)

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derivative of

2 cos (2 x)

- 4 sin (2 x)

Solution steps

\frac{d}{d x} (2 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 2 (- sin (2 x) \cdot 2)

Simplify

= - 4 sin (2 x)

f (x) = \frac{ln ( x ^{2} )}{x}

f (x) = e^{- 5 x} cos (3 x)

\frac{d}{d x} (sin (x + sin (2 x)))

\int_{- 1}^{2} (x + 2) - (x^{2}) d x

x \to 0 lim (\frac{x + 5}{x})

What is the derivative of 2cos(2x) ?
The derivative of 2cos(2x) is -4sin(2x)
What is the first derivative of 2cos(2x) ?
The first derivative of 2cos(2x) is -4sin(2x)