What is (\partial)/(\partial x)((x^2+3y^2)^7) ?

The answer to (\partial)/(\partial x)((x^2+3y^2)^7) is 14x(x^2+3y^2)^6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)((x^2+3y^2)^7)

\frac{\partial}{\partial x} ((x^{2} + 3 y^{2})^{7})

14 x (x^{2} + 3 y^{2})^{6}

Solution steps

\frac{\partial}{\partial x} ((x^{2} + 3 y^{2})^{7})

Treat

y

as a constant

Apply the chain rule:

7 (x^{2} + 3 y^{2})^{6} \frac{\partial}{\partial x} (x^{2} + 3 y^{2})

= 7 (x^{2} + 3 y^{2})^{6} \frac{\partial}{\partial x} (x^{2} + 3 y^{2})

\frac{\partial}{\partial x} (x^{2} + 3 y^{2}) = 2 x

= 7 (x^{2} + 3 y^{2})^{6} \cdot 2 x

Simplify

= 14 x (x^{2} + 3 y^{2})^{6}

\frac{\partial}{\partial x} (x^{4} y^{2} - x^{3} y)

\int 16 x (8 x^{2} + 2)^{2} d x

y^{^{'}} + 8 y = 4

e^{4 x}, 0

\int 2 x^{3} - 5 x^{2} + 3 x + 1 d x

What is (\partial)/(\partial x)((x^2+3y^2)^7) ?
The answer to (\partial)/(\partial x)((x^2+3y^2)^7) is 14x(x^2+3y^2)^6