What is the solution for 2(dy)/(dt)+y=0,y(0)=-3 ?

The solution for 2(dy)/(dt)+y=0,y(0)=-3 is y=-3/(e^{t/2)}

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2(dy)/(dt)+y=0,y(0)=-3

2 \frac{d y}{d t} + y = 0, y (0) = - 3

y = - \frac{3}{e ^{\frac{t}{2}}}

Solution steps

2 \frac{d y}{d t} + y = 0

Solve linear ODE:

y = - \frac{3}{e ^{\frac{t}{2}}}

y = - \frac{3}{e ^{\frac{t}{2}}}

ln (2) \cdot 2^{x^{2} + 2} x

(0.4) (6)

x \to 2 + lim (- 6 x^{2} + 14)

\frac{d}{d x} (ln (sec (5 x) + tan (5 x)))

\int e^{x} \cdot \frac{1}{2 x} d x

What is the solution for 2(dy)/(dt)+y=0,y(0)=-3 ?
The solution for 2(dy)/(dt)+y=0,y(0)=-3 is y=-3/(e^{t/2)}