What is the integral of (13)/(x(x^2+25)) ?

The integral of (13)/(x(x^2+25)) is 13(1/25 ln|x|-1/50 ln|x^2+25|)+C

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integral of (13)/(x(x^2+25))

\int \frac{13}{x ( x ^{2} + 25 )} d x

13 (\frac{1}{25} ln ∣ x ∣ - \frac{1}{50} ln x^{2} + 25) + C

Solution steps

\int \frac{13}{x ( x ^{2} + 25 )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 13 \cdot \int \frac{1}{x ( x ^{2} + 25 )} d x

Take the partial fraction of

\frac{1}{x ( x ^{2} + 25 )} : \frac{1}{25 x} - \frac{x}{25 ( x ^{2} + 25 )}

= 13 \cdot \int \frac{1}{25 x} - \frac{x}{25 ( x ^{2} + 25 )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 13 (\int \frac{1}{25 x} d x - \int \frac{x}{25 ( x ^{2} + 25 )} d x)

\int \frac{1}{25 x} d x = \frac{1}{25} ln ∣ x ∣

\int \frac{x}{25 ( x ^{2} + 25 )} d x = \frac{1}{50} ln x^{2} + 25

= 13 (\frac{1}{25} ln ∣ x ∣ - \frac{1}{50} ln x^{2} + 25)

Add a constant to the solution

= 13 (\frac{1}{25} ln ∣ x ∣ - \frac{1}{50} ln x^{2} + 25) + C

\int_{3}^{11} \frac{1}{2 x + 3} d x

x^{\frac{9}{6}}

f (x) = - 10 x^{2} + 1760 x - 50000

f (t) = 9 t - 2 t^{2}

y^{^{''}} - 2 y^{^{'}} + y = 3 e^{t} cos (t)

What is the integral of (13)/(x(x^2+25)) ?
The integral of (13)/(x(x^2+25)) is 13(1/25 ln|x|-1/50 ln|x^2+25|)+C