What is the tangent of f(x)=x+(17)/x ,\at x=1 ?

The tangent of f(x)=x+(17)/x ,\at x=1 is y=-16x+34

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tangent of f(x)=x+(17)/x ,\at x=1

tangent of

f (x) = x + \frac{17}{x}, at x = 1

y = - 16 x + 34

Solution steps

Find the tangent point:

(1, 18)

Find the slope of

f (x) = x + \frac{17}{x} : \frac{df ( x )}{d x} = 1 - \frac{17}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 16

Find the line with slope m=

- 16

and passing through

(1, 18) : y = - 16 x + 34

y = - 16 x + 34

\frac{d}{d x} (\frac{x}{x + 19})

\frac{d y}{d x} = - \frac{4 sin ( x ) cos ( x )}{y}

x \to 2 lim (x^{2} - 2 x + 1)

\int ln (x) \cdot e^{- 2 x} d x

f (x) = \frac{2 x - 1}{x + 5}, at x = 3

What is the tangent of f(x)=x+(17)/x ,\at x=1 ?
The tangent of f(x)=x+(17)/x ,\at x=1 is y=-16x+34