What is the derivative of e^x+e^e+ex ?

The derivative of e^x+e^e+ex is e+e^x

What is the first derivative of e^x+e^e+ex ?

The first derivative of e^x+e^e+ex is e+e^x

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\frac{d}{d x} (e^{x} + e^{e} + e x)

e + e^{x}

Solution steps

\frac{d}{d x} (e^{x} + e^{e} + e x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (e^{e}) + \frac{d}{d x} (e x)

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (e^{e}) = 0

\frac{d}{d x} (e x) = e

= e^{x} + 0 + e

Simplify

= e + e^{x}

\frac{9 t}{4 + t ^{2}}

n = 3 \sum \infty \frac{1}{n}

3 - 5 x

\frac{d}{d x} (\frac{3 x}{t - 3})

\frac{\partial}{\partial x} (\frac{8 x y ^{2}}{x ^{2} + y ^{2}})

What is the derivative of e^x+e^e+ex ?
The derivative of e^x+e^e+ex is e+e^x
What is the first derivative of e^x+e^e+ex ?
The first derivative of e^x+e^e+ex is e+e^x