What is the derivative of 8sqrt(x)-x^2 ?

The derivative of 8sqrt(x)-x^2 is 4/(sqrt(x))-2x

What is the first derivative of 8sqrt(x)-x^2 ?

The first derivative of 8sqrt(x)-x^2 is 4/(sqrt(x))-2x

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\frac{d}{d x} (8 x - x^{2})

\frac{4}{x} - 2 x

Solution steps

\frac{d}{d x} (8 x - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (8 x) = \frac{4}{x}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{4}{x} - 2 x

f (x) = 3 x^{7}

\frac{\partial}{\partial x} (\frac{3 x - t}{4 s + 5 t})

\frac{d}{d t} (4 t e^{- t})

f (x) = \frac{x ^{2}}{x ^{2} - 16}

\int 5 cos^{4} (3 x) d x

What is the derivative of 8sqrt(x)-x^2 ?
The derivative of 8sqrt(x)-x^2 is 4/(sqrt(x))-2x
What is the first derivative of 8sqrt(x)-x^2 ?
The first derivative of 8sqrt(x)-x^2 is 4/(sqrt(x))-2x