What is the derivative of 9pix^2 ?

The derivative of 9pix^2 is 18pix

What is the first derivative of 9pix^2 ?

The first derivative of 9pix^2 is 18pix

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derivative of

9 π x^{2}

18 π x

Solution steps

\frac{d}{d x} (9 π x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 π \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 π 2 x^{2 - 1}

Simplify

= 18 π x

\int \frac{1}{1 + 81 x ^{2}} d x

(2 x sin (y) cos (y)) y^{^{'}} = 4 x^{2} + sin^{2} (y)

\frac{d}{d x} (tan (e^{6 x}) + e^{t a n (6 x)})

\frac{\partial}{\partial y} (e^{x} sin (2 y))

\int (14 x^{13}) d x

What is the derivative of 9pix^2 ?
The derivative of 9pix^2 is 18pix
What is the first derivative of 9pix^2 ?
The first derivative of 9pix^2 is 18pix