What is the integral from 7 to 11 of 2/(x^3) ?

The integral from 7 to 11 of 2/(x^3) is 72/5929

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integral from 7 to 11 of 2/(x^3)

\int_{7}^{11} \frac{2}{x ^{3}} d x

\frac{72}{5929}

Decimal

0.01214 \dots

Solution steps

\int_{7}^{11} \frac{2}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{7}^{11} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{7}^{11}

= 2 [- \frac{1}{2 x ^{2}}]_{7}^{11}

Compute the boundaries:

\frac{36}{5929}

= 2 \cdot \frac{36}{5929}

Simplify

= \frac{72}{5929}

\frac{\partial}{\partial y} ((9 x - 4 y) (12 x + 2 y))

8 a^{6} - 14 a^{3} - 15

\int_{1}^{3} \frac{x + 1}{x ( x ^{2} + 1 )} d x

f (x) = 2 x^{2} - x^{4}, (1, 1)

\int_{1}^{8} \frac{ln ( x )}{x ^{2}} d x

What is the integral from 7 to 11 of 2/(x^3) ?
The integral from 7 to 11 of 2/(x^3) is 72/5929