What is the solution for ydy-xdx=0 ?

The solution for ydy-xdx=0 is y=sqrt(x^2+c_{1)},y=-sqrt(x^2+c_{1)}

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ydy-xdx=0

y d y - x d x = 0

y = x^{2} + c_{1}, y = - x^{2} + c_{1}

Solution steps

y d y - x d x = 0

Solve separable ODE:

y = x^{2} + c_{1}, y = - x^{2} + c_{1}

y = x^{2} + c_{1}, y = - x^{2} + c_{1}

(y - y x^{2}) y^{^{'}} = (y + 1)^{2}

\frac{d}{d x} (y cos (x y))

5 x^{2}, x^{2} + 4

x^{2} y^{^{'}} + x y = 8

\frac{\partial}{\partial x} (4 x y + 3)

What is the solution for ydy-xdx=0 ?
The solution for ydy-xdx=0 is y=sqrt(x^2+c_{1)},y=-sqrt(x^2+c_{1)}