What is the solution for y'=y(1-0.0008y) ?

The solution for y'=y(1-0.0008y) is y=-(e^{t+c_{1}})/(1-0.0008e^{t+c_{1)}}

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y'=y(1-0.0008y)

y^{^{'}} = y (1 - 0.0008 y)

y = - \frac{e ^{t + c_{1}}}{1 - 0.0008 e ^{t + c_{1}}}

Solution steps

y^{'} (t) = y (1 - 0.0008 y)

Solve separable ODE:

y = - \frac{e ^{t + c_{1}}}{1 - 0.0008 e ^{t + c_{1}}}

y = - \frac{e ^{t + c_{1}}}{1 - 0.0008 e ^{t + c_{1}}}

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What is the solution for y'=y(1-0.0008y) ?
The solution for y'=y(1-0.0008y) is y=-(e^{t+c_{1}})/(1-0.0008e^{t+c_{1)}}